Hi,

you might want to check the coordinates of the second carbon atom. (0.3333,
0.3333, 0.3333) means that the z-coordinate of the second atom is ~8
Angstrom, while that of the first is 0 Ang. Marcos probably made a typo in
that post you areusing as a reference and meant (0.3333, 0.3333, 0.0)
instead of (0.3333, 0.3333, 0.3333).

Roland


On 17 September 2012 09:08, bedamani singh <[email protected]> wrote:

> I am a new user of siesta and have been trying to find the bandstructure
> of graphene.
>
> As the correct selection of K-points in the first brilluion zone is a
> prequisite for calculating the bandstructure. I am at loss as how to find
> the coordintes of K points in the reciprocal space. I have done
> calculations from the reference (
> http://www.mail-archive.com/[email protected]/msg00935.html) with the
> atomic positions at (0,0,0); (0.3333, 0.3333, 0.3333) in fractional
> cordinates for C atoms and the lattice cell is used as
>
> LatticeConstant 2.44 Ang
>
> %block LatticeParameters
>
> 1.00 1.00 10.0 90.0 90.0 60.0
>
> %endblock LatticeParameters
>
>  Relaxation was done MD.VariableCell (.true.) and kgrid _Monkhorst_Pack
> is used as
>
> %block kgrid_Monkhorst_Pack
>
> 6 0 0 0.0
>
> 0 6 0 0.0
>
> 0 0 1 0.0
>
> %endblock kgrid_Monkhorst_Pack
>
> The coordinates of the Kpoints are calculated using a =1.42 angstrom in
> the relations
>
> Gamma= (0,0,0) ; K= (2pi/a)(1/3,0,0) ; and M=(2pi/a)(1/3,1.732/9,0) and
> used
>
>  BandLinesScale pi/a
>
> %block bandlines
>
> 1 1.476 0.000 0.000 K
>
> 51 0.000 0.000 0.000 /Gamma
>
> 101 1.476 0.852 0.000 M
>
> %endblock bandlines
>
>  I am tring to compare the observed bandstructure with those reported by
> J. C. Charlier et al. (See the attached pdf file)(" Electron and phonon
> properties of graphene: their relationship with carbon nanotubes"
> DOI:10.1007/978-3-540-72865-8_21). But the two results are not matching.
> The input fdf, my observed bandstructure and bandstructure of J. C.
> Charlier et al. are attached. Anyone please help in finding the true
> K-points.
>
>

Responder a