I haven't used awk much but a better way would be to do 'grep -v
patternyoudontwanttomatch'. maybe put quotes around the pattern or
something.
I can't sleep so I debugged the rest of it. This works properly:
read var
awk "\$0 !~ /$var/ {print}" file
paul
--
You can tune a piano, but you can't tuna fish.
You can tune a filesystem, but you can't tuna fish.
-- from the tunefs(8) man page
On Tue, 23 May 2000, David Smith wrote:
> I'm writing a Bourne shell script, and I've run into a snag.
> I want to read in a variable and pass the string in that variable
> to awk.
>
> Something like this:
>
> read $var
> awk '$0 !~ /$var/ {print}' file
>
> This deletes any line containing $var. Unfortunately, it won't work
> as I have it because my quoting is wrong. I've tried all the
> permutations, and I'm stumped. Can someone straighten me out?
>
> This was my best attempt:
>
> awk "'\$0 !~ /"$var"/ {print}"
>
> and I got the error "Invalid char ''' in expression." It means
> the first '.
>
> Also, is there a better way to selectively delete lines from input?
>
> Thanks,
> Dave
>
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