OOOPS! Pressed send without writing anything.
Which was going to be only that, I'll put it on the 'to do' list Roger...along with those other things I have promised. Would be interesting. Ivan. ----- Original Message ----- From: <rogalt...@aol.com> To: <silver-list@eskimo.com> Sent: Monday, 23 October 2000 02:07 Subject: Re: CS>Re: Interesting, simple H202 experiment > In a message dated 10/21/00 2:01:21 AM EST, i...@win.co.nz writes: > > << The reaction : > 2(Ag) + H2O2 + 2H+ + 2e > 2(Ag+ + e) + 2H2O > > E(cell) = 0.977 V > log K = 33.06168 > K = 1.15e33 > deltaG= -188.53169 kJ/mol > > has H2O2 stripping 2 electrons from Ag which probably forms the HO- > radical intermediary which then combines with free H+ ions (H3O+) to > form water. Somewhere in there is a gas phase but it would seem that gas > is not a product at all...no wonder people had trouble measuring the gas > production. > This will proceed only in neutral or acid water where there are free > hydronium ions, > > Ivan: Is the above statement based on your experience, or thermodynamic > reasoning? If based on the latter, you have to remember that in order for the > free energy to come out to be -188.5 KJ/mole, reactants and products must be > in there standard states (OK, XS CS and H2O are already in their respective > standard states) which is not the case for the kind of conditions for CS > production and H2O2 doping we envision since H+, H2O2, and Ag+ will not be > their respective standard states. As an interesting exercise, substitute a > few FINAL pH values, Ag+ concentrations and H2O2 doping concentrations just > to see under what range of these variables the reaction above would still > proceed to the right. Another way to look at it is to assume equilibrium, > i.e., delta G = 0 and solve for Ag+ after assuming a variety of FINAL pH > values, and H2O2 concentrations. You might find that this reaction proceeds > to the right at pH values well above 6 or 7 and with even minute > concentrations of H2O2. (I'd do it myself, but I lost my slide rule 30 years > ago and now you can't find any replacements the Internet) Roger -- The silver-list is a moderated forum for discussion of colloidal silver. To join or quit silver-list or silver-digest send an e-mail message to: silver-list-requ...@eskimo.com -or- silver-digest-requ...@eskimo.com with the word subscribe or unsubscribe in the SUBJECT line. To post, address your message to: silver-list@eskimo.com Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <mdev...@eskimo.com>
