In a message dated 8/3/2001 11:19:28 AM Eastern Daylight Time, mdud...@execonn.com writes:
> I have seen the same thing, but reached a different conclusion. I assumed > that although the H2O2 "dissolved" the smaller particles, it reduced the > size of the larger ones as well so that I still ended up with a bunch of > smaller ones > which gave a TE with no larger ones. > > Marshall > Marshall: As I said earlier, the CS particle size you end up with will be a function of the H2O2: total CS particle ratio. I don't believe this interaction is linear. Instead, it's likely to follow a highly skewed (asymmetric) parabolic relationship. Roger
