Terry et al, It's not that simple. If each jar was EXACTLY the same as the others, then yes, the current would divide equally. But they will not be exactly the same. One of them will have a lower resistance than the others, and will draw more current. Thus the ppm production for that jar will be higher than the others, making the resistance go down faster than the others, drawing more current than the others, producing even more ppm than the others, dropping the resistance even more than the others, hogging even more of the current, and so on. It wouldn't surprise me if you had at least a 20% variation in final strength amongst the jars.
You would produce more consistent CS product using one large jar that hold the contents of 10 or 20 smaller jars. Or put the jars in series and take much longer to produce your product. --Steve ----- Original Message ----- From: "Terry Chamberlin" <tcj...@yahoo.ca> To: <silver-list@eskimo.com> Sent: Thursday, April 18, 2002 10:15 PM Subject: CS>25 ma > Dean said, > "Is that 25 mA for one jar, or for the 10 parallel > jars (if 10 jars, then the current is 2.5 mA per jar)" > > I hadn't thought of that. I knew that the voltage > stayed the same in parallel, but it never occurred to > me that the current was split up over the 10 jars. > > So if I used 20 jars, I would be brewing each jar at > 1.25 ma? > > > > > ______________________________________________________________________ > Find, Connect Date! http://personals.yahoo.ca > > > -- > The silver-list is a moderated forum for discussion of colloidal silver. > > To join or quit silver-list or silver-digest send an e-mail message to: > silver-list-requ...@eskimo.com -or- silver-digest-requ...@eskimo.com > with the word subscribe or unsubscribe in the SUBJECT line. > > To post, address your message to: silver-list@eskimo.com > Silver-list archive: http://escribe.com/health/thesilverlist/index.html > List maintainer: Mike Devour <mdev...@eskimo.com> >
