Hi..

There's a much simpler way to do this.  Just divide 3% by 35%.  3/35 =
.0857. Multiply this
times any size container you want to fill to get the amount of 35% to put in
and top off with water.
.0857 x 500 ml = 42.85 ml.

Al
----- Original Message -----
From: "Ian Roe" <ian_onta...@hotmail.com>
To: <silver-list@eskimo.com>
Sent: Wednesday, December 04, 2002 9:24 AM
Subject: Re: CS>Titration Math


> Hi:
>
> Yes but if I do this, I have to mix it up in a separate container and
repour
> etc.  I was trying to avoid this.  I was trying to determine how much 35%
to
> put in the bottle to start with so I wouldn't have to mix and repour.
>
> Ian Roe
>
> ----- Original Message -----
> From: "Dean Miller" <dtmil...@midiowa.net>
> To: <silver-list@eskimo.com>
> Sent: Tuesday, December 03, 2002 6:07 PM
> Subject: Re: CS>Titration Math
>
>
> > On Tue, 3 Dec 2002 15:53:45 -0500, "Ian Roe" <ian_onta...@hotmail.com>
> > wrote:
> >
> > >Can someone here show me the formula for dilution. I knew how to do
this
> once but I just can't remember now.
> > >
> > >Problem: wish to put an unknown volume of 35% H2O2 into a 250 ml and a
> 500 ml container and fill with distilled water to obtain 3%.
> >
> > If you're not too picky (IOW, you want something close to 3% and
> > aren't using it for quantitative analysis), and since H2O2 and water
> > have about the same weight per volume -- just mix 1 part H2O2 with 11
> > parts of water.  That'll produce about 3% H2O2.  (A 1/9 mixture will
> > be 3.5%).
>
>
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