Hi Mike, the answer is that even pure water dissociates to a limited
degree, providing ions of
H2O + H2O == H3O(+) + OH(-) according to the Bronsted Lowry concept,
or(and)
H2O == H(+) +OH(-)
both of these reactions being reversible, and at 25*C producing
concentrations of
hydrogen ion (or hydronium ion) of 1.0*10(-7) moles per liter as well
as the same
hydroxide ion concentration of 1.0*10(-7) Moles per
liter. Hence, ultimately, the log base ten pH scale is derived where pH
= log(1/H(+)), or for pure water at 25*C:
pH = log(1/1.0*10(-7)) = log(10(7)) = 7.
The Bronsted Lowry Proton Transfer theory takes note of the fact that a
Hydrogen ion H(+) is just a proton, since it lost it's one electron when it
became an ion. This proton will immediately attach itself to a molecule of
water forming the hydronium ion, above,or (in non-water solutions, for
instance) to a more basic molecule or ion.
Take care, Malcolm
At 01:57 AM 10/12/03 -0400, you wrote:
url: http://escribe.com/health/thesilverlist/m63420.html
CS>Re: Measuring ppms
From: Jrowland
Date: Sat, 11 Oct 2003 21:37:00
> OK---to what does the Pure Water Test reading get compared?
> jr
Depends on what you want to do. Now I have a question for you. You
are an oldtimer on the list, and may have come across a discussion
about it.
Electrons cannot propagate in an electrolyte. Current flow is
through the movement of ions only.
BTW, Mike, this is not strictly true, but it may be so for aqueous
electrolytes - dunno.
Hey, if water swaps protons around in the form of hydronium ions, does that
mean it's a semiconductor and 'holes' propagate??
In the cs process, some trace contaminants must already be in the
water in the form of ions in order to start the process.
The ions in the vicinity of each electrode move to their respective
electrodes and gain or lose electrons as appropriate.
The ones further away may know an electric field is present, but
their drift velocity due to the electric field is perhaps orders of
magnitude less than their thermal velocity, and much less than the
diffusion velocity.
Diffusion velocity?? If I'm going 100 mph back and forth randomly, and at
the same time I'm propagating steadily toward San Francisco at 10 mph, I'm
gonna get there; the traffic opposing me cannot be any thicker than the
traffic going my way.
So the ions basically cannot respond to the applied electric field.
This resurfaces a question in my mind, will the electric field provoke
increased ionisation in pure water?
Yet for electrolysis to begin, there must be a continuous path
through the water from one electrode to the other.
Why?
I don't know the answer. If you can figure it out, please tell me.
Best Regards,
Mike Monett
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