Subclause 3.1 says the following: "When a proxy goes to route a message to a UA for which it has a binding, it can use any one of the flows on which a successful registration has been completed. A failure to deliver a request on a particular flow can be tried again on an alternate flow. Proxies can determine which flows go to the same UA by comparing the instance-id."
Note that the text says "can use ONE of the flows". So, to me that doesn't mean that the request will be forked on multiple flows. Regards, Christer -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Christer Holmberg Sent: Monday, October 06, 2008 9:50 AM To: Juha Heinanen Cc: [email protected]; [EMAIL PROTECTED] Subject: Re: [Sip] Dual registration without Outbound Hi, >>If you want to do that you simply register the same AoR twice using basic 3261 registration, without Outbound, and the >>inbound call will be forked. > >are you saying that if i use outbound, then the inbound call will NOT get forked (which would be very bad)? I thought the whole idea of outbound was that the registrar chooses ONE flow, and switches to another flow is the previous doesn't work. But, it does not fork onto multiple flows. Or, have I missunderstood everything??? Regards, Christer _______________________________________________ Sip mailing list https://www.ietf.org/mailman/listinfo/sip This list is for NEW development of the core SIP Protocol Use [EMAIL PROTECTED] for questions on current sip Use [EMAIL PROTECTED] for new developments on the application of sip _______________________________________________ Sip mailing list https://www.ietf.org/mailman/listinfo/sip This list is for NEW development of the core SIP Protocol Use [EMAIL PROTECTED] for questions on current sip Use [EMAIL PROTECTED] for new developments on the application of sip
