Uhmmm, the awk script you listed will only add the second fields
of lines 3 and 6, not the second fields of lines 3 *TO* 6. Admittedly,
Shre's question was rather ambiguous.
You may need to change that to:
#!/bin/awk -f
NR == 3 {
num1 = $2;
}
(NR > 3) && (NR <= 6) {
num1 = $2 + num1;
}
NR > 6 {
print num1;
exit;
}
Or even better :) :), change that to:
#!/usr/bin/perl -w
while (<STDIN>) {
$i++;
next if $i < 3;
last if $i > 6;
$total += (split)[1];
}
print "$total\n";
Craig Southeren writes:
> The AWK script below will do this. Save it into a file called "addnums",
> make it executable with chmod +x, and run it with:
>
> addnums datafn
>
> where datafn in the name of the file with the data in it.
>
>
> #!/bin/awk -f
>
> NR == 3 {
> num1 = $2;
> }
>
> NR == 6 {
> print $2 + num1;
> exit;
> }
>
>
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Shrestha
> Sent: Friday, 7 January 2000 15:07
> To: [EMAIL PROTECTED]
> Subject: [SLUG] addition using script file
>
>
> Suppose there is a file, which contains:
>
> a 12
> b 14
> g 9
> p 58
> d 25
> t 18
> w 32
>
>
> The two fields are seperated by space.
> If we have to add all the numbers of second field using script file, it
> can be done using cut -d" " -f2 /file
>
> Can any one help to write a script file which adds the number from third
> line to sixth line only.
>
> Any help will be highly appreciated!!
>
> Shre
>
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