I did this; <? echo "<img src=\"images/$image\">"; ?> Which does the samething :) thanks > >> When I link to it with the variable image, I want the variable image >> to be subbed for a image inside a <img src="images/$image"> line >> inside blah.php script. > > You may want: > > <img src="images/<?php echo $image; ?>"> > > Del > > -- > SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/ > More Info: http://slug.org.au/lists/listinfo/slug -- SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/ More Info: http://slug.org.au/lists/listinfo/slug
