Hi Sluggers: Here is my problem.
In an SQL table I have a field defined as "TEXT". I have the following scenario: $variable = "Some Text"; $data = "This is $variable that I am testing"; In SQL when I insert or update the TEXT field with $data, all I get in the db is "This is that I am testing" . How do I get it to show the $variable data. MY SQL statement was "update tablename set textfield='$data'" If anyone can help, please let me know. Louis -- SLUG - Sydney Linux User's Group - http://slug.org.au/ More Info: http://lists.slug.org.au/listinfo/slug
