On Tue, 2003-07-08 at 15:11, Bill Bennett wrote: > I've a rather exotic Compact Disk that I'd like to copy. > Two symphonies, each of three movements. > > Unfortunately, whoever laid out this disc had probably been > smoking substances: each movement is separated by 2 seconds and > the symphonies by 3. > > I can rip the disc without difficulty. > > When I burn it, I'd like to separate the movements with > (approximately) 15 seconds and the symphonies by (approximately) 30. > > On looking over man cdrecord, the -pad option seems to be what's > the matter. It pads the audio data to be a multiple of 2352 bytes. > > Unfortunately, I don't know what this equates to in seconds. > > Can anyone help, please? >
The 'padsize=' option looks like a better bet. "To pad the equivalent of 20 minutes on a CD, you may write padsize=20x60x75s." So you might try padsize=30x75s (the s refers to sectors, not seconds.) The manual says this needs to be specified for each track though. The pad option seems to just increase the file by only a little until the total size is a multiple of 2352 bytes. CD audio is 16bits per channel at 44KHz, which works out to 176000 bytes per second, so 2352 bytes is approximately bugger all ;) -- Felix Sheldon <[EMAIL PROTECTED]> -- SLUG - Sydney Linux User's Group - http://slug.org.au/ More Info: http://lists.slug.org.au/listinfo/slug