Grant, 

> protecting themselves against unwanted traffic. The user must 
> agree to the 
> terms of the provider (how that's going to work I don't know 
> ++) which 
> includes not deliberately disrupting other users or doing 
> anything illegal +++.
> 
> ++ I'd like to know as it's a potential second stage to a project I'm
> quoting on. One idea is that all web/proxy access results in 
> redirection to the terms & conditions site, no other 
> ports/routing occurs until form filled out and/or payment made.

Was recently travelling in europe and stumbled upon a couple public
hotspots in hotels etc. The way they all worked was that they were
essentially open to all, but your IP or MAC (or both) were blocked to
the internet. You were redirected to a page to enter in your credit card
details and once you bought credit, you could login and logout of the
system through a web interface - this would essentially block and
unblock your access and also of course stop the timer.

Great setup - pitty the hotspots I found were pretty expensive (EUR10
for 2 hours) but internet cafes/hotspots in europe are generally pretty
expensive compared to our cafés.
 
> +++ Almost all ISP's insist you not do anything illegal even 
> though they
> don't check. However, if somebody complains and they can 
> prove it, they 
> cut you off and/or advise authorities. It's going to be potentially 
> difficult to track down wireless culprits, especially if 
> they've hijacked 
> somebody else's connection... but hey, if they can do it for phones...

Look below...
 
> Can you change the MAC address of wireless cards? How long before the 
> Taiwanese build one you can change?

Yes you can. Question is in this instance, can you have two MAC
addresses (different cards) on the same network at the same time?? I
suspect this would cause some havoc, or would it??

If you cant have two MAC's on the same network at the same time, there
is no way to hijack really (???) because the person has logged off,
hence blocking that MAC.

Feel free to correct me!

Cheers
Adam.


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