On Sun, Dec 13, 2009 at 4:36 PM, david <da...@kenpro.com.au> wrote: > this is something I do all the time and it works perfectly, but I'm sure > there is a more elegant way to do it: > > > $ for i in *.tif ; convert $i $i.jpg; done > $ for i in $i.jpg ; do mv $i `echo $i | sed s/.tif//`; done > > Apart from specific examples, where do I look in the bash book for a better > way to remove the <.tif> part of the output filename, or other such > substitutions?
This is one way: $ for i in *.tif; do convert $i `basename $i .tif`.jpg; done - Gonzalo -- SLUG - Sydney Linux User's Group Mailing List - http://slug.org.au/ Subscription info and FAQs: http://slug.org.au/faq/mailinglists.html
