>>>>> "lists" == lists <li...@sbt.net.au> writes:
lists> I have a basic script that includes an exit on a date month lists> condition, like so: lists> /snip/ grep -q '07/2014' part2 && exit 0 /snip/ lists> I would like to add multiple additional non consecutive lists> individual day date conditions, like say, 15/06/2014, 20/06, lists> 25/06, like so; lists> grep -q '07/2014' part2 && exit 0 grep -q '15/06/2014' lists> part2 && exit 0 grep -q '20/06/2014' part2 && exit 0 grep -q lists> '25/06/2014' part2 && exit 0 lists> I guess that would work OK, but, what's a good way to put all lists> '06' entries in a single grep, egrep or how? As you're not using regular expressions, but just strings, fgrep is the way to do it. fgrep -q '07/2014 15/06/2014 20/06/2014 25/06/2014' part 2 && exit 0 lists> thanks lists> V lists> -- SLUG - Sydney Linux User's Group Mailing List - lists> http://slug.org.au/ Subscription info and FAQs: lists> http://slug.org.au/faq/mailinglists.html -- SLUG - Sydney Linux User's Group Mailing List - http://slug.org.au/ Subscription info and FAQs: http://slug.org.au/faq/mailinglists.html