Your server class method should have the signature:
public void testInteger(int abc) {
..
SOAP handles the conversion back from the wrapper class to the appropriate
primitive type.
Hope it helps,
Phill.
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
Sent: 26 March 2002 15:12
To: [EMAIL PROTECTED]
Subject: how do I pass Integer?
Hello all,
I've tried to search in the archive but cant find the solution of
my problem. Actually it's very simple that I feel kind of silly to post
this thread: i need to pass integer to my method in java class in
soap's server side.
In Apache SOAP v2.2 Documentation it's stated as follow:
To make life a little easier, a set of type mappings has been
predefined and registered into the SOAPMappingRegistry for the SOAP
encoding style. These include mappings for the following Java types:
all Java primitive types, such as int, float, boolean, byte, etc.
and their corresponding wrapper classes (i.e. java.lang.Integer,
java.lang.Boolean, etc.)
please correct me if i'm wrong, IMHO it means I don't have to make a
mapping?
so here's method in server side:
public void testInteger(Integer abc) {
System.out.println("testInteger = " + abc.intValue());
}
and here's how SOAP client call that method:
<java_client>
call.setMethodName("testReturnInt");
call.setEncodingStyleURI(encodingStyleURI);
Vector params = new Vector();
int arg = 10;
Integer arg1 = new Integer(arg);
params.addElement(new Parameter("arg123", Integer.class,
arg1, null));
call.setParams(params);
// Invoke the call.
Response resp;
// other irrelevant codes
</java_client>
and here's the error
Generated fault:
Fault Code = SOAP-ENV:Server
Fault String = Exception while handling service request:
com.mycompany.MySOAPServer.testInteger(int) -- no signature match
please tell me what part that i miss.
thank you very much in advance.
--
Best regards,
dion
mailto:[EMAIL PROTECTED]
