Re: [RCSE] XP 4.5 wing length

[Raschow]

In a message dated 7/1/2006 10:41:37 A.M. Eastern Standard Time, [EMAIL PROTECTED] writes: Tom If you consider dihedral it might be on the spot for 4 degrees on ech side cos ( 2X4degrees) X 59.525" = 58.945 No - that calculation would give the wingspan for 8 deg on each side (if 59.525 is the span with no dihedral).  The correct calculation is 2 x (59.525 / 2) x cos4deg, or just 59.525 x cos 4deg = 59.38 (draw a diagram!).  Good Lift