The statvfs struct dose not have any information about the disk, only the
filesystem.  It will report the logical filesystem size of all the disks
in your array.

--- Ankit Mehta <[EMAIL PROTECTED]> wrote:
> Hello Everyone,
> 
> I am working on a utility to monitor the free space
> left on the disk(s) on which a file resides. The
> filename that I pass to statvfs() could potentially be
> spread over multiple disks. I was wondering if anyone
> came across such a situation and what would be the
> statistics returned by statvfs() in the statvfs struct
> in such a scenario. Any insight on this would be
> helpful.
> 
> Thanks
> -Ankit
> 
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