Thank you Walter. I liked your solution! This is what I was looking for i.e.
&boost=log(sum(1,qty)) O. O. Walter Underwood wrote > The usual fix for this is log(1+qty). If you might have negative values, > you can use log(max(1,qty)). > > wunder > Walter Underwood > wunder@ > http://observer.wunderwood.org/ > > On Oct 20, 2014, at 3:04 PM, O. Olson < > olson_ord@ > > wrote: > >> I am considering using a boost as follows: >> >> &boost=log(qty) >> >> Where qty is the quantity in stock of a given product i.e. qty could be >> 0, >> 1, 2, 3, … etc. The problem I see is that log(0) is -Infinity. Would this >> be >> a problem for Solr? For me it is not a problem because >> log(0) < log(1) < log(2) etc. >> >> I'd be grateful for any thoughts. One alternative is to use max e.g. >> &boost=max(log(qty), -1) >> >> But still this would cause Solr to compute the -Infinity and then discard >> it. So can I use an expression for boost that would result in –Infinity? >> >> Thank you >> O. O. >> -- View this message in context: http://lucene.472066.n3.nabble.com/Is-there-a-problem-with-Infinity-as-boost-tp4165036p4165189.html Sent from the Solr - User mailing list archive at Nabble.com.
