Thanks Alot Upayavira. It worked as expected.
On Tue, Sep 8, 2015 at 2:09 PM, Upayavira <u...@odoko.co.uk> wrote:
> you can add bq= inside your {!synonym_edismax} section, if you wish and
> it will apply to that query parser only.
>
> Upayavira
>
> On Mon, Sep 7, 2015, at 03:05 PM, dinesh naik wrote:
> > Please find below the detail:
> >
> > My main query is like this:
> >
> > q=(((_query_:"{!synonym_edismax qf='itemname OR itemnumber OR itemdesc'
> > v='HTC' mm=100 synonyms=true synonyms.constructPhrases=true
> > synonyms.ignoreQueryOperators=true}") OR (itemname:"HTC" OR
> > itemnamecomp:HTC* OR itemnumber:"HTC" OR itemnumbercomp:HTC* OR
> > itemdesc:"HTC"~500)) AND (warehouse:Ind02 OR warehouse:Ind03 OR
> > warehouse:Ind04 ))
> >
> > Giving Boost of 1000 for warehouse Ind02
> > using below parameter:
> >
> > bq=warehouse:Ind02^1000
> >
> >
> > Here i am expecting a boost of 1004 but , somehow 1000 is added extra may
> > be because of my additional parser. How can i avoid this?
> >
> >
> > Debug information for the boost :
> >
> > <str name="document1">
> > 2004.0 = sum of:
> > 1004.0 = sum of:
> > 1003.0 = sum of:
> > 1001.0 = sum of:
> > 1.0 = max of:
> > 1.0 = weight(itemname:HTC in 235500) [CustomSimilarity], result
> > of:
> > 1.0 = fieldWeight in 235500, product of:
> > 1.0 = tf(freq=1.0), with freq of:
> > 1.0 = termFreq=1.0
> > 1.0 = idf(docFreq=26, maxDocs=1738053)
> > 1.0 = fieldNorm(doc=235500)
> > 1000.0 = weight(warehouse:e02^1000.0 in 235500)
> > [CustomSimilarity],
> > result of:
> > 1000.0 = score(doc=235500,freq=1.0), product of:
> > 1000.0 = queryWeight, product of:
> > 1000.0 = boost
> > 1.0 = idf(docFreq=416190, maxDocs=1738053)
> > 1.0 = queryNorm
> > 1.0 = fieldWeight in 235500, product of:
> > 1.0 = tf(freq=1.0), with freq of:
> > 1.0 = termFreq=1.0
> > 1.0 = idf(docFreq=416190, maxDocs=1738053)
> > 1.0 = fieldNorm(doc=235500)
> > 2.0 = sum of:
> > 1.0 = weight(itemname:HTC in 235500) [CustomSimilarity], result
> > of:
> > 1.0 = fieldWeight in 235500, product of:
> > 1.0 = tf(freq=1.0), with freq of:
> > 1.0 = termFreq=1.0
> > 1.0 = idf(docFreq=26, maxDocs=1738053)
> > 1.0 = fieldNorm(doc=235500)
> > 1.0 = itemnamecomp:HTC*, product of:
> > 1.0 = boost
> > 1.0 = queryNorm
> > 1.0 = sum of:
> > 1.0 = weight(warehouse:e02 in 235500) [CustomSimilarity], result
> > of:
> > 1.0 = fieldWeight in 235500, product of:
> > 1.0 = tf(freq=1.0), with freq of:
> > 1.0 = termFreq=1.0
> > 1.0 = idf(docFreq=416190, maxDocs=1738053)
> > 1.0 = fieldNorm(doc=235500)
> > 1000.0 = weight(warehouse:e02^1000.0 in 235500) [CustomSimilarity],
> > result of:
> > 1000.0 = score(doc=235500,freq=1.0), product of:
> > 1000.0 = queryWeight, product of:
> > 1000.0 = boost
> > 1.0 = idf(docFreq=416190, maxDocs=1738053)
> > 1.0 = queryNorm
> > 1.0 = fieldWeight in 235500, product of:
> > 1.0 = tf(freq=1.0), with freq of:
> > 1.0 = termFreq=1.0
> > 1.0 = idf(docFreq=416190, maxDocs=1738053)
> > 1.0 = fieldNorm(doc=235500)
> > </str>
> >
> > On Mon, Sep 7, 2015 at 7:21 PM, dinesh naik <dineshkumarn...@gmail.com>
> > wrote:
> > Hi all,
> >
> > Is there a way to apply different boost , using bq parameter for
> > different
> > parser.
> >
> > for example if i am using a synonym parser and edismax parser in a single
> > query, my bq param value is getting applied for both the parser making
> > the
> > boost value double.
> >
> > --
> > Best Regards,
> > Dinesh Naik
> >
> >
> >
> >
> >
> > On Mon, Sep 7, 2015 at 7:21 PM, dinesh naik <dineshkumarn...@gmail.com>
> > wrote:
> >
> > > Hi all,
> > >
> > > Is there a way to apply different boost , using bq parameter for
> different
> > > parser.
> > >
> > > for example if i am using a synonym parser and edismax parser in a
> single
> > > query, my bq param value is getting applied for both the parser making
> the
> > > boost value double.
> > >
> > > --
> > > Best Regards,
> > > Dinesh Naik
> > >
> >
> >
> >
> > --
> > Best Regards,
> > Dinesh Naik
>
--
Best Regards,
Dinesh Naik
