Hello, Sorry to disturb. Is there anyone here able to reproduce and verify this issue?
Many thanks, Markus -----Original message----- > From:Markus Jelsma <markus.jel...@openindex.io> > Sent: Wednesday 9th May 2018 18:25 > To: solr-user <solr-user@lucene.apache.org> > Subject: Solr 7.3, FunctionScoreQuery no longer displays debug output > > Hi, > > Is this a known problem? For example, the following query: > q=australia&debug=true&boost=if(exists(query($bqlang)),2,1)&bqlang=lang:en&defType=edismax&qf=content_en > content_ro > > returns the following toString for 7.2.1: > boost(+(Synonym(content_en:australia content_en:australia) | > Synonym(content_ro:austral > content_ro:australia)),if(exists(query(lang:en,def=0.0)),const(2),const(1))) > > 7.3: > FunctionScoreQuery(+(Synonym(content_en:australia content_en:australia) | > Synonym(content_ro:austral content_ro:australia)), scored by > boost(if(exists(query(lang:en,def=0.0)),const(2),const(1)))) > > and the following debug output for 7.2.1: > > 11.226025 = boost((Synonym(content_en:australia content_en:australia) | > Synonym(content_ro:austral > content_ro:australia)),if(exists(query(lang:en,def=0.0)),const(2),const(1))), > product of: > 11.226025 = max of: > 11.226025 = weight(Synonym(content_ro:austral content_ro:australia) in > 6761) [SchemaSimilarity], result of: > 11.226025 = score(doc=6761,freq=18.0 = termFreq=18.0 > ), product of: > 5.442921 = idf(docFreq=193, docCount=44720) > 2.0625 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1) from: > 18.0 = termFreq=18.0 > 1.2 = parameter k1 > 0.0 = parameter b (norms omitted for field) > 1.0 = if(exists(query(lang:en,def=0.0)=0.0),const(2),const(1)) > > but for 7.3 i get only: > > 11.226025 = product of: > 1.0 = boost > 11.226025 = boost(if(exists(query(lang:en,def=0.0)),const(2),const(1))) > > The scores are still the same, but the debug output is useless. Removing the > boost fixes the problem of debug output immediately. > > Thanks, > Markus > >
