The blog looks like it's going to be useful from now on, so I'll take a look.Thank you.
What I wanted, however, was a way to know what field was boosted as a result. But I couldn't find a way to do that, so instead I tried to get the field and value out of the resulting score by putting a binary bit on the field/value pair. It doesn't really matter to me whether you do it additively or multiplicatively, as it's good to know the field boosted as a result. Do you see what I mean? 2020年3月20日(金) 18:56 Alessandro Benedetti <a.benede...@sease.io>: > Hi Taisuke, > there are various ways of approaching boosting and scoring in Apache Solr. > First of all you must decide if you are interested in multiplicative or > additive boost. > Multiplicative will multiply the score of your search result by a certain > factor while the additive will just add the factor to the final score. > > Using advanced query parsers such as the dismax and edismax you can use the > : > *boost* parameter - multiplicative - takes function in input - > > https://lucene.apache.org/solr/guide/6_6/the-extended-dismax-query-parser.html#TheExtendedDisMaxQueryParser-TheboostParameter > *bq*(boost query) - additive - > > https://lucene.apache.org/solr/guide/6_6/the-dismax-query-parser.html#TheDisMaxQueryParser-Thebq_BoostQuery_Parameter > *bf*(boost function) - additive - > > https://lucene.apache.org/solr/guide/6_6/the-dismax-query-parser.html#TheDisMaxQueryParser-Thebf_BoostFunctions_Parameter > > This blog post is old but should help : > https://nolanlawson.com/2012/06/02/comparing-boost-methods-in-solr/ > > Then you can boost fields or even specific query clauses: > > 1) > > https://lucene.apache.org/solr/guide/6_6/the-dismax-query-parser.html#TheDisMaxQueryParser-Theqf_QueryFields_Parameter > > 2) q= features:2^1.0 AND features:3^5.0 > > 1.0 is the default, you are multiplying the score contribution of the term > by 1.0, so no effect. > features:3^5.0 means that the score contribution of a match for the term > '3' in the field 'features' will be multiplied by 5.0 (you can also see > that enabling debug=results > > Finally you can force the score contribution of a term to be a constant, > it's not recommended unless you are truly confident you don't need other > types of scoring: > q= features:2^=1.0 AND features:3^=5.0 > > in this example your document id: 3 will have a score of 6.0 > > Not sure if this answers your question, if not feel free to elaborate more. > > Cheers > > -------------------------- > Alessandro Benedetti > Search Consultant, R&D Software Engineer, Director > www.sease.io > > > On Thu, 19 Mar 2020 at 11:18, Taisuke Miyazaki <miyazakitais...@lifull.com > > > wrote: > > > I'm using Solr 7.5.0. > > I want to get boosted field and values per documents. > > > > e.g. > > documents: > > id: 1, features: [1] > > id: 2, features: [1,2] > > id: 3, features: [1,2,3] > > > > query: > > bq: features:2^1.0 AND features:3^1.0 > > > > I expect results like below. > > boosted: > > - id: 2 > > - field: features, value: 2 > > - id: 3 > > - field: features, value: 2 > > - field: features, value: 3 > > > > I have an idea that set boost score like bit-flag, but it's not good I > > think because I must send query twice. > > > > bit-flag: > > bq: features:2^2.0 AND features:3^4.0 > > docs: > > - id: 1, score: 1.0(0x001) > > - id: 2, score: 3.0(0x011) # have feature:2(2nd bit is 1) > > - id: 3, score: 7.0(0x111) # have feature:2 and feature:3(2nd and 3rd > > bit are 1) > > check score value then I can get boosted field. > > > > Is there a better way? > > >
