Not sure i fully understand, If "facet.method=enum steps over all terms in the index for that field", than what does setting the q=field:subset do? if i set the q=*:*, than how do i get the frequency only on my subset? Ofer
On Thu, Apr 21, 2011 at 4:40 PM, Yonik Seeley <yo...@lucidimagination.com>wrote: > On Thu, Apr 21, 2011 at 9:24 AM, Ofer Fort <o...@tra.cx> wrote: > > Another strange behavior is that the Qtime seems pretty stable, no matter > > how many object match my query. 200K and 20K both take about 17s. > > I would have guessed that since the time is going over all the terms of > all > > the subset documents, would mean that the more documents, the more time. > > facet.method=enum steps over all terms in the index for that field... > that takes time regardless of how many documents are in the base set. > > There are also short-circuit methods that avoid looking at the docs > for a term if it's docfreq is low enough that it couldn't possibly > make it into the priority queue. Because if this, it can actually be > faster to facet on a larger base set (try *:* as the base query). > > Actually, it might be interesting to see the query time if you set > facet.mincount equal to the number of docs in the base set - that will > test pretty much just the time to enumerate over the terms without > doing any set intersections at all. Be careful not to set mincount > greater than the number of docs in the base set though - solr will > short-circuit that too and skip enumeration altogether. > > The work on the bulkpostings branch should definitely speed up your > case even more - but I have no idea when it will "land" on trunk. > > > -Yonik > http://www.lucenerevolution.org -- Lucene/Solr User Conference, May > 25-26, San Francisco >
