you should reverse your sort algorithm. maybe you can override the tf
method of Similarity and return -1.0f * tf(). (I don't know whether
default collector allow score smaller than zero)
Or you can hack this by add a large number or write your own
collector, in its collect(int doc) method, you can do like this:
collect(int doc){
float score=scorer.score();
score*=-1.0f;
....
}
if you don't sort by relevant score, just set Sort
On Tue, May 1, 2012 at 10:38 PM, Yuval Dotan <yuvaldo...@gmail.com> wrote:
> Hi Guys
> We have a use case where we need to get the 50 *latest *documents that
> match my query - without additional ranking,sorting,etc on the results.
> My index contains 1,000,000,000 documents and i noticed that if the number
> of found documents is very big (larger than 50% of the index size -
> 500,000,000 docs) than it takes more than 5 seconds to get the results even
> with rows=50 parameter.
> Is there a way to get the results faster?
> Thanks
> Yuval
