We have 300M documents, each about a paragraph of text on average. The index
is 140GB in size. I'm not sure how to find the IDF score, was that in the
debug query below?

It seems that any query with the word "book" in it triggers a 15 sec
response time (unless it's the 2nd time we run the same query). Looking at
terms, 'book' is the 2nd highest term with 90M documents in the index.

Calling 'book' a stop word doesn't seem reasonable, and while that article
on bigrams and common grams is fascinating, I wonder if it addresses this
situation, in which we aren't really likely to manage a bi-gram phrase match
between the search "book sales improvement", and the terms in the document:
"category book marketing and sales today the real guide to improving" right?
I think this is what's happening here, everything with a common phrase
"category book" is getting included, which seems logical and correct. 



-----Original Message-----
From: Jan Høydahl [mailto:jan....@cominvent.com] 
Sent: Thursday, March 21, 2013 5:43 PM
To: solr-user@lucene.apache.org
Subject: Re: Slow queries for common terms

Hi,

I think you can start by reading this blog
http://www.hathitrust.org/blogs/large-scale-search/slow-queries-and-common-w
ords-part-2 and try out the approach using a dictionary of the most common
words in your index.

You don't say how many documents, avg. doc size, the IDF value of "book",
how much RAM, whether you utilize disk caching well enough and many other
things which could affect this situation. But the pure fact that only a few
common search words trigger such a delay would suggest commongrams as a
possible way forward.

--
Jan Høydahl, search solution architect
Cominvent AS - www.cominvent.com
Solr Training - www.solrtraining.com

21. mars 2013 kl. 11:09 skrev David Parks <davidpark...@yahoo.com>:

> I've got a query that takes 15 seconds to return whenever I have the 
> term "book" in a query that isn't cached. That's a pretty common term 
> in our search index. We're indexing about 120 GB of text data. We only 
> store terms and IDs, no document data, and the disk is virtually 
> unused, it's all CPU time.
> 
> 
> 
> I haven't done much yet to optimizing and scale solr, as we're only 
> trying to support a small number of users in a private beta. I 
> currently only have a couple of gigs of ram dedicated to Solr (we've 
> ordered more hardware for it, but it's not in yet).
> 
> 
> 
> I wonder if there's something I can do in the short term to alleviate 
> the problem. Many searches work great, but these ones that take 15+ 
> sec are a black eye. I'd be happy with a short term fix followed in 
> the near future by a more proper long-term fix.
> 
> 
> 
> If I were to take a stab at this I'd say the following two are the 
> short and long term solutions:
> 
> .         Short: Configure solr to short-circuit quries, thus reducing
query
> quality, but guaranteeing a certain response time (I'm ok with this 
> tradeoff, but is this possible or contains risks I need to consider 
> more?)
> 
> .         Long: Implement sharding, get more hardware resources for these
> boxes and split up the index across multiple servers.
> 
> 
> 
> Am I on track in my thinking here?
> 
> Thanks,
> 
> David
> 
> 
> 
> My long query:
> 
> <?xml version="1.0" encoding="UTF-8"?>
> 
> <response>
> 
> 
> 
> <lst name="responseHeader">
> 
>  <int name="status">0</int>
> 
>  <int name="QTime">15464</int>
> 
>  <lst name="params">
> 
>    <str name="debugQuery">true</str>
> 
>    <str name="indent">true</str>
> 
>    <str name="q">cook book fourth baby
> 
> </str>
> 
>    <str name="wt">xml</str>
> 
>  </lst>
> 
> </lst>
> 
> <result name="response" numFound="91695127" start="0">
> 
>  <doc>
> 
>    <str name="id">1004505170125</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428753459934396420</long></doc>
> 
>  <doc>
> 
>    <str name="id">1005401904542</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428760446538612739</long></doc>
> 
>  <doc>
> 
>    <str name="id">1003707566177</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428772178357125123</long></doc>
> 
>  <doc>
> 
>    <str name="id">1000610053924</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428787238421921794</long></doc>
> 
>  <doc>
> 
>    <str name="id">1000611651986</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428796273825153026</long></doc>
> 
>  <doc>
> 
>    <str name="id">1001419625706</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428823418682212355</long></doc>
> 
>  <doc>
> 
>    <str name="id">1004804435353</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428823070202658818</long></doc>
> 
>  <doc>
> 
>    <str name="id">1000514089336</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428755943804370945</long></doc>
> 
>  <doc>
> 
>    <str name="id">1000329540261</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428805063523958786</long></doc>
> 
>  <doc>
> 
>    <str name="id">1001607999738</str>
> 
>    <long name="facetime">0</long>
> 
>    <long name="_version_">1428757460650295298</long></doc>
> 
> </result>
> 
> <lst name="debug">
> 
>  <str name="rawquerystring">cook book fourth baby
> 
> </str>
> 
>  <str name="querystring">cook book fourth baby
> 
> </str>
> 
>  <str name="parsedquery">all:cook all:book all:fourth all:babi</str>
> 
>  <str name="parsedquery_toString">all:cook all:book all:fourth 
> all:babi</str>
> 
>  <lst name="explain">
> 
>    <str name="1004505170125">
> 
> 10.476225 = (MATCH) product of:
> 
>  13.9683 = (MATCH) sum of:
> 
>    7.988946 = (MATCH) weight(all:cook in 3428426) [DefaultSimilarity], 
> result of:
> 
>      7.988946 = score(doc=3428426,freq=2.0 = termFreq=2.0
> 
> ), product of:
> 
>        0.5447923 = queryWeight, product of:
> 
>          5.925234 = idf(docFreq=931212, maxDocs=128248074)
> 
>          0.091944434 = queryNorm
> 
>        14.664206 = fieldWeight in 3428426, product of:
> 
>          1.4142135 = tf(freq=2.0), with freq of:
> 
>            2.0 = termFreq=2.0
> 
>          5.925234 = idf(docFreq=931212, maxDocs=128248074)
> 
>          1.75 = fieldNorm(doc=3428426)
> 
>    0.29064935 = (MATCH) weight(all:book in 3428426) 
> [DefaultSimilarity], result of:
> 
>      0.29064935 = score(doc=3428426,freq=1.0 = termFreq=1.0
> 
> ), product of:
> 
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> 
>          1.3440113 = idf(docFreq=90917737, maxDocs=128248074)
> 
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> 
>          1.0 = tf(freq=1.0), with freq of:
> 
>            1.0 = termFreq=1.0
> 
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> 
>          1.75 = fieldNorm(doc=3428426)
> 
>    5.688705 = (MATCH) weight(all:babi in 3428426) [DefaultSimilarity], 
> result of:
> 
>      5.688705 = score(doc=3428426,freq=1.0 = termFreq=1.0
> 
> ), product of:
> 
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> 
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> 
>          1.0 = tf(freq=1.0), with freq of:
> 
>            1.0 = termFreq=1.0
> 
>          5.9460006 = idf(docFreq=912073, maxDocs=128248074)
> 
>          1.75 = fieldNorm(doc=3428426)
> 
>  0.75 = coord(3/4)
> 
> </str>
> 
>    <str name="1005401904542">
> 
> 10.476225 = (MATCH) product of:
> 
>  13.9683 = (MATCH) sum of:
> 
>    7.988946 = (MATCH) weight(all:cook in 4132020) [DefaultSimilarity], 
> result of:
> 
>      7.988946 = score(doc=4132020,freq=2.0 = termFreq=2.0
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>    0.29064935 = (MATCH) weight(all:book in 4132020) 
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> 
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> 
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> 
>        0.12357436 = queryWeight, product of:
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> 
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> 
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> 
>          1.75 = fieldNorm(doc=4132020)
> 
>    5.688705 = (MATCH) weight(all:babi in 4132020) [DefaultSimilarity], 
> result of:
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> 
> ), product of:
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> 
>          1.75 = fieldNorm(doc=4132020)
> 
>  0.75 = coord(3/4)
> 
> </str>
> 
>    <str name="1003707566177">
> 
> 10.476225 = (MATCH) product of:
> 
>  13.9683 = (MATCH) sum of:
> 
>    7.988946 = (MATCH) weight(all:cook in 2139457) [DefaultSimilarity], 
> result of:
> 
>      7.988946 = score(doc=2139457,freq=2.0 = termFreq=2.0
> 
> ), product of:
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>          5.925234 = idf(docFreq=931212, maxDocs=128248074)
> 
>          1.75 = fieldNorm(doc=2139457)
> 
>    0.29064935 = (MATCH) weight(all:book in 2139457) 
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> 
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> 
> ), product of:
> 
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>  0.75 = coord(3/4)
> 
> </str>
> 
>    <str name="1000610053924">
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> 10.476225 = (MATCH) product of:
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>  13.9683 = (MATCH) sum of:
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>    7.988946 = (MATCH) weight(all:cook in 1862392) [DefaultSimilarity], 
> result of:
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>      7.988946 = score(doc=1862392,freq=2.0 = termFreq=2.0
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> 
>          1.75 = fieldNorm(doc=1862392)
> 
>    0.29064935 = (MATCH) weight(all:book in 1862392) 
> [DefaultSimilarity], result of:
> 
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> 
> ), product of:
> 
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