You're fro loop could be speeded with a generator : root.__set_children__( i for i in root.__get_children__() if i is not child )
But I dont really understand the propose qof you try except. (in most case, a bare except is avery bad idea (since it begin to catch Syntax error and such.) On 3 juil. 07, at 01:44, Lunpa, The wrote: > Thats good in some cases for persistent widgets that you have a known > quantity of at all times. > > I've built a work around, since the closest thing I can find is > __get_children__() and __set_children__() > Its a bit crude, but it works, so I'll post it: > > def remove_widget(child, root=None): > """Because there is no RootWidget.remove_child(foo) method!""" > try: > if not root: > root = soya.root_widget > old_children = root.__get_children__() > children = [ ] > for i in old_children: > if i != child: > children.append(i) > > root.__set_children__(children) > return True > except: > return False > > > On 7/2/07, Holcroft Jean-Baptiste <[EMAIL PROTECTED]> wrote: >> maybe you can hide your child >> >> 2007/7/2, Lunpa, The <[EMAIL PROTECTED]>: >>> Once a child has been added to in pudding (such as with >>> pudding.RootWidget.add_child), is there a good way to _remove_ >>> it? I >>> can't find anything like pudding.RootWidget.remove_child() or >>> whatnot. >>> >>> _______________________________________________ >>> Soya-user mailing list >>> Soya-user@gna.org >>> https://mail.gna.org/listinfo/soya-user >>> >> >> >> _______________________________________________ >> Soya-user mailing list >> Soya-user@gna.org >> https://mail.gna.org/listinfo/soya-user >> >> > > > -- > This email message is public domain. Have a nice day! ^_^ > > _______________________________________________ > Soya-user mailing list > Soya-user@gna.org > https://mail.gna.org/listinfo/soya-user > -- marmoute _______________________________________________ Soya-user mailing list Soya-user@gna.org https://mail.gna.org/listinfo/soya-user