Oleg Verych wrote:
+ uint32_t vx;
+ int dp;
+
+ if (vhi) {
+ vx = vhi;
+ dp = 0;
+ } else {
+ vx = (uint32_t) v;
`v' is a data in memory, accessed with 32-bits cast, thus operation
yields high 32-bits part of `v'.
Bullsh*t. That would be *(uint32_t *)&v. Casting between integer types
truncate the high bits regardless of platform endianness.
-hpa
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