The main thing with this method is that you have to be "adaptative"", you have to be able to put an orange sticker next to a red center at the beginning and not lose time because of that.
This can be done with training :-) Gilles. 2005/12/12, Mike Bennett <[EMAIL PROTECTED]>: > --- In [email protected], Gilles van den > Peereboom <[EMAIL PROTECTED]> wrote: > > > > Thank you, > > That's I asked ACube to do but your solution is better. > > However it's still very very long and you can't resonably finish with > > such an algorithm on the 3x3x3. > > Another possibility is to fix the centers at the beginning. > > But then it just goes back to a normal Fridrich Solve. > > > > So I guess I won't look much more into that possibility, maybe I'll > > from time to time do the cross on one side and fix the center but it > > needs to be a very lucky case then. > > > > Thanks :-) > > Gilles. > > You could always use cases when the cross is already solved on the > opposite side, and finish the solve with M'E2ME2. If there are any > nice blocks or pairs, this may work better than F2R2B2L2. > > -Mike > > > > > > > > Yahoo! Groups Links > > > > > > > ------------------------ Yahoo! Groups Sponsor --------------------~--> Fair play? Video games influencing politics. Click and talk back! http://us.click.yahoo.com/u8TY5A/tzNLAA/yQLSAA/MXMplB/TM --------------------------------------------------------------------~-> Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/speedsolvingrubikscube/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
