--- In [email protected], "darereck" <[EMAIL PROTECTED]
.> wrote:
>
> I remember Stefan posted an algorithm he used. There was two. I
can't
> find it. Could someone please post both of them?
(I'm assuming you use Bob's the numbering scheme)
Thanks for asking, you made me think about it again and I just
realized my right hand is pretty much holding the cube while the left
hand does all the work, and that despite the case being symmetric. So
I gotta try mirroring it.
Right now I do it this way:
r' U' (x U) R' U' x l' l' U L U' R' U x
So now I'll have to try:
l U (x U') L U x r r U' R' U L U' x
Btw, here's another alg for another OLL case I found recently:
L F' F' U R' U' F' U l D' (x U') L'
Cheers!
Stefan
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