Travis,
that's the most worthwhile advice I've read on this forum in some
time. Just keep it as simple as possible. The more complex one makes
the math the greater the opportunity for a digit, a decimal, a square, a
square root, take your pick, to applied incorrectly, and thus skew the
results to where they're no longer relevant.
Look at equation 4.9.3 in -291. It's exactly the same equation you
quoted. Very simple.
29.84 * c * d² * √p*
*
Of course, I suppose the charts in -291 could be helpful if you
didn't need the results calculated out to tenths of a gallon. They're
all the result of the same equation with a C = 1.00 so converting to a
different hydrant outlet coefficient is relatively easy.
See disclaimer below.
sincerely,
*Ken Wagoner, SET
*Parsley Consulting***
*350 West 9th Avenue, Suite 206
*Escondido, California 92025
*****Phone 760-745-6181*
Visit our website <http://www.parsleyconsulting.com/>
IMPORTANT NOTICE: This correspondence is not a Formal Interpretation
issued pursuant to NFPA Regulations. Any opinion expressed is the
personal opinion of the author and does not necessarily represent the
official position of the NFPA or its Technical Committees. In addition,
this correspondence is neither intended, nor should it be relied upon,
to provide professional consultation or services
It should be noted that the above is my opinion as a member of the NFPA
Installation of Private Fire Service Mains and their Appurtenances
Committee in accordance with the NFPA Regulations Governing Committee
Projects and should therefore not be considered, nor relied upon, as the
official position of the NFPA or its Committees
***
On 10/01/2016 11:51 AM, Travis Mack wrote:
Follow the formula in the standards.
29.83 x hydrant coefficient x pumper modification x diameter x
diameter x sqrt (pitot pressure)
Keep it all simple. No need to overcomplicate everything.
There are even several apps to put in your phone to do this stuff.
Keep it all simple.
Travis Mack, SET
MFP Design, LLC
"Follow" us on Facebook:
https://www.facebook.com/pages/MFP-Design-LLC/92218417692
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Sent from my iPhone
On Oct 1, 2016, at 11:35 AM, Brad Casterline <[email protected]
<mailto:[email protected]>> wrote:
My pleasure Jeff, thanks for saying.
On Oct 1, 2016 1:32 PM, "Jeff Normand" <[email protected]
<mailto:[email protected]>> wrote:
Thanks for sharing Brad.
On Sat, Oct 1, 2016 at 1:28 PM, Brad Casterline
<[email protected] <mailto:[email protected]>> wrote:
Say it's a 2.5" butt (small, smooth and well rounded my
personal favorite) so C=.9.
((2.5/24) ^2) * PI = .034 ft^2.
.034 * .9 = .0307 ft^2.
Say pitot = 30 PSI.
30/.433=69.284 ft (h).
v=(2gh)^.5=(2*32.2*69.284)^.5=69.8 ft/sec.
.0307 ft^2 * 69.8 ft/sec = 2.05 ft^3/sec, * 7.48 * 60 = 920 GPM.
That's not too shabby!
Brad
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