i'm not sure if i understand what u want, but u can do nested join( prev_join, table_next). Also see the full spec of select( columns_list, whereclause, from_obj_list, order_by, group_by, ....)
something like table_a.join(table_b).join(c).join(d).select([<columns_here>]) for the implicit version of join, may do the job if there is only one obvious relation from table to table. If not, u have to specify onclauses on each join and use the explicit join(t1,t2,onclause). Maybe give some better example (at last 3 tables/columns)? > Hi, > I've trying to solve the following problem. I've given a list of > tables and list of columns to look at. > All tables are auto-loaded from DB. So, I don't know a priory (I > don't want to know) the relationships and table schema. Now, how to > build a general join among tables and retrieve only the list of > given columns names. As an example, there is an explicit join call > and I can do > > join(tableObj1, tableObj2).select() > > but selection will be done for all columns and as of my > understanding join can do only 2 tables. > > Can it be generalized to a list of tables and can selection be done > only on given column names? > > Thanks, > Valentin. > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
