On Dec 5, 2007, at 1:56 PM, David Gardner wrote:
> > I have three tables a(a query of a really), b, c > > a has a 1-many relationship with b > c has a 1-many relationship with b > > What I would like to do is in my mapper for table c, is sort the order > of rows from b by a.name. > I don't know how to do this or if it is possible. What I have looks > like: > > sql_a = select([table_a], table_a.c.col1='some > value').alias('a_query') > > mapper(B, b_table, properties = { > 'A' : relation(sql_a, lazy=False, > primaryjoin=(sql_a.c.id==table_b.c.a_id))}) > > mapper(C, c_table, properties = { > 'Bs' : relation(B, backref='C', cascade='all, delete-orphan', > order_by=[C.A.name, c_table.c.value1, > c_table.c.value2]), > }) > > This gets me an "AttributeError: 'InstrumentedAttribute' object has no > attribute 'name'" this error is becuase C.A is not a gateway to the columns on the "A" mapper. > > > I have also tried: > order_by=[A.name > and > order_by=[sql_a.c.name > > both get me this: ProgrammingError: (ProgrammingError) missing > FROM-clause entry for table "sql_a.name" this error is because the relation from C->B has no relationship to "A"s table at all, and it is not used in the generated query. to have "A"s table be a part of it in all cases, youd have to map A's column onto B's mapper, which is fairly messy: mapper(B, select([b_table, a.c.name], b_table.c.a_id==a.c.id)) you can try creating this mapper as a "non-primary" mapper and using it for just the C->B relation: s = select([b_table, a.c.name], b_table.c.a_id==a.c.id) mapper(C, ctable, properties={ 'bs':relation(mapper(B, s, non_primary=True), order_by=[s.c.name]) }) I havent tried the above myself so see if it works for you. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---