Thanks! I'll try that out Mike
On Dec 18, 3:55 pm, Michael Bayer <[EMAIL PROTECTED]> wrote:
> On Dec 18, 2007, at 9:49 AM, voltron wrote:
>
>
>
> > I am trying to retrieve unique users from a table using this:
>
> > results = sa_session.query(TempScore).group_by(TempScore.user_name)
>
> > This unfortunately causes the error below:
>
> > "There was a problem: (ProgrammingError) column "temp_scores.id" must
> > appear in the GROUP BY clause or be used in an aggregate function"
>
> > Could someone tell me what the SA 0.4 syntax would be for this query?
> > I am using Postgresql
>
> all columns that arent in an aggregate must be in the GROUP BY, so to
> get every column in, do this:
>
> sess.query(TempScore).group_by([c for c in TempScore.c])
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"sqlalchemy" group.
To post to this group, send email to sqlalchemy@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/sqlalchemy?hl=en
-~----------~----~----~----~------~----~------~--~---
