On Tue, Apr 8, 2008 at 1:00 PM, Jonathan Ellis <[EMAIL PROTECTED]>
wrote:

>
> session.query(Action).filter(Action.task.has(Task.connection.has(Connection.caller==caller1)))
>
>
Yep--that's what I'm doing now.  It has the effect of creating another
nested subselect, but I'm not too concerned about that as both are
relatively cheap EXISTS queries.


-- 
Tim Lesher <[EMAIL PROTECTED]>

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