With a backref, both ends of the relationship are aware of each other -- if you append object b1 to the collection a.b, then a backref b1.a will be updated immediately. If you had two different relationships, you wouldn't see an update to b1.a until you reload the object.
It seems like it'd be nice if they worked the same -- perhaps there's a good reason it doesn't. I think 0.4 has an error check for some cases of mutual relationships (A->B, B->A). Maybe the check is not in place for M:N relationships? Barry ----- Original Message ---- From: Bobby Impollonia <[EMAIL PROTECTED]> To: sqlalchemy@googlegroups.com Sent: Sunday, May 4, 2008 5:28:56 PM Subject: [sqlalchemy] Re: Duplication of rows in many-to-many relationship I thought that defining relation with a backref was just a convenient shorthand for defining two relations. This makes it sound like are practical differences between the two techniques. Is this true? What are the differences? Also, does having the unique key that you recommend stop SA from trying to add the duplicate? Or will it try anyway and then get a SQL exception due to the violated constraint? I am often doing if a not in b.as: b.as.append(a) and I have been wondering if there is a way to just do: b.as.append(a) and have SA automatically check if it was already in collection and shouldn't be added again. On Sun, May 4, 2008 at 4:40 PM, Barry Hart <[EMAIL PROTECTED]> wrote: > > By chance, in your mappers, are you declaring two relationships instead of > one relation with a backref? > > As a side note, once you straighten this out, you may want to declare the > composite (a_id, b_id) as a unique key on the relation table. > > Barry > > > ----- Original Message ---- > From: Karlo Lozovina <[EMAIL PROTECTED]> > To: sqlalchemy <sqlalchemy@googlegroups.com> > Sent: Sunday, May 4, 2008 4:31:55 PM > Subject: [sqlalchemy] Duplication of rows in many-to-many relationship > > > Let's say I have two classes A and B, and I want instances of both > classes, to have a list of each other, that is, many-to-many > relationship. For a shorthand, "a" means instance of A, and "b" is an > instance of B. > > For example: "a.bs" is a list, full of instances of class B. > Similarly, "b.as" is a list, full of instances of class A. In > modelling that relationship I use three tables, one for As, one for > Bs, and one for their relationship. If I only append instances of B to > some "a.bs", then save all those objects, everything works fine. But > if I append instances of A and B, both to "a.bs" and "b.as", then > save, I get double rows in the third table. Is there a way around > that? > > P.S. > In a very likely case I haven't been completely understood, I'll > attach some code to demonstrate my point ;). > > Thanks all. > > ________________________________ > Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it > now. > > > > ____________________________________________________________________________________ Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---