On May 22, 2008, at 5:51 PM, Jeff Putsch wrote:

> Which can give me two selects using aliases:
>
> a1 = s.correlate(None).alias()
> a2 = s.correlate(None).alias()
>
> But every attempt at using a1 and a2 in a select with a join is
> failing for me.

a1.join(a2, <onclause>) should do it.  if not, supply a full test case  
and a description of the specific problem.


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