Hi,
Apologies for lowering the general IQ of the list, I'm very new to web apps
and databases.
I had a declarative table:
class ArkContact(Base):
"""
table of all contacts
"""
__tablename__ = 'contacts'
id = Column(Integer, primary_key=True)
project_id = Column(Integer, ForeignKey('projects.id'))
client_id = Column(Integer, ForeignKey('clients.id'))
firstname = Column(String)
lastname = Column(String)
email1 = Column(String)
email2 = Column(String)
workphone = Column(Integer)
mobile = Column(Integer)
project = relation(ArkProject, backref=backref('contacts',
order_by=func.lower(firstname)))
client = relation(ArkClient, backref=backref('contacts',
order_by=func.lower(firstname)))
All is good,
I added a new column in:
lastcontact = Column(DateTime)
Now I'm getting errors when I try to connect:
<class 'sqlalchemy.exc.OperationalError'>: (OperationalError) no such
column: contacts.lastcontact u'SELECT contacts.id AS contacts_id,
contacts.project_id AS contacts_project_id, contacts.client_id AS
contacts_client_id, contacts.firstname AS contacts_firstname,
contacts.lastname AS contacts_lastname, contacts.email1 AS contacts_email1,
contacts.email2 AS contacts_email2, contacts.workphone AS
contacts_workphone, contacts.mobile AS contacts_mobile, contacts.lastcontact
AS contacts_lastcontact \nFROM contacts ORDER BY lower(contacts.firstname)'
[]
Am I being extremely naive in thinking there would be some way of 'updating'
the table to show the new column?
Many thanks,
Jules
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