On Mon, Nov 10, 2008 at 10:05 AM, King Simon-NFHD78 <[EMAIL PROTECTED]> wrote:
> Actually, the section after that (Using Subqueries) probably does > something very close to what you want. What's the result of these lines: > > q1 = (session.query(Snapshot.strategy, Snapshot.symbol, sum_pnl) > .group_by(Snapshot.strategy, Snapshot.symbol) > .having(sum_pnl<-15000)).subquery() > > q2 = (session.query(Snapshot.strategy, func.count('*')) > .join(q1, Snapshot.strategy = q1.c.strategy) > .groupby(Snapshot.strategy)) I assume you mean '=='? I get a foreign key error on the join:: sum_pnl = func.sum(Snapshot.pnl) q1 = (session.query(Snapshot.strategy, Snapshot.symbol, sum_pnl) .group_by(Snapshot.strategy, Snapshot.symbol) .having(sum_pnl<-15000)).subquery() q2 = (session.query(Snapshot.strategy, func.count('*')) .join(q1, Snapshot.strategy==q1.c.strategy) .groupby(Snapshot.strategy)) File "/home/titan/johnh/dev/lib/python2.4/site-packages/SQLAlchemy-0.5.0rc3dev_r5205-py2.4.egg/sqlalchemy/sql/util.py", line 109, in join_condition raise exc.ArgumentError( ArgumentError: Can't find any foreign key relationships between 'snapshot' and '{ANON 157186924 anon}' Still playing with the aliases in the link you referred me to above but haven't gotten there yet... --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---