technically you'd say query(X).join(X.all_A.as_type(C)) but I don't know offhand if that use case has been implemented for join() as of yet. you can of course just say query(X).join((A, A.id==x.aid), (C, C.id==A.id)) assuming you're on joined table inheritance. all bets are off for concrete.
[EMAIL PROTECTED] wrote: > > hi > > i have A, B, C,... inheritance, where A points to some X. > how i query all Xs which are pointed by, say Cs ? > > if i put a backref on the reference, > query(X).join( X.all_A) will give me As Bs Cs everything... > > or should that go down to joins? > > ciao > svil > > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
