On 10 Apr, 12:52, a...@svilendobrev.com wrote: > that's what i have in bitemporal queries. > u need a groupby and subquery/ies.
I see, thanks for your hint! I tried to do it with bare SQL via pgadmin, and I ended up with select d.id, c.id from d left outer join ( select c.* from c join ( select d_id, max(value) as v from c group by d_id) as sub on c.d_id = sub.d_id and c.value = sub.v) as c on c.d_id = d.id Now I'll try with the Query API :) But I was wondering, maybe there's a simpler way than 3 nested queries...? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---