On Sun, Apr 12, 2009 at 19:21, Michael Bayer <mike...@zzzcomputing.com>wrote:
> use a seperate join() call for each path. join(path1, path2, path3 ...)
> assumes thats one path along related entities.
>
Thanks! Just in case anyone interested, here is final (working) code:
clauses = []
if skill:
q = q.join('profile', 'skills')
clauses.append(Skill.name == skill)
if city:
q = q.join('profile', 'city')
clauses.append(City.name == city)
members = q.filter(and_(*clauses))
--
Max.Ischenko // twitter.com/maxua
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