> > 1. the backref is invalid. you're attempting to create a relation called > "services" twice on the same class. > 2. the relation is self-referential - it can't be automatically determined > which join to apply for Service->service_type_table and > service_type_table->Service - you need to use both "primaryjoin" and > "secondaryjoin" to define this. examples are > athttp://www.sqlalchemy.org/docs/05/mappers.html#specifying-alternate-j... > .
In example there are two classes class User(object): pass class Address(object): pass but I have only one It it possible to make join like "Service 2 marked table B can contain Service 1, 3 marked table A in the same table" [service] id table name code 1 A service1 9843904 2 B serivce2 4394343 3 A service3 6632901 [service_btype] service_b_id service_a_id 2 1 2 3 --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---