Yes, you can map a class against an arbitrary select, not just a
table, see:

http://www.sqlalchemy.org/docs/mappers.html#mapping-a-class-against-arbitrary-selects

So above you have a query that you could map a class against (you
might want to add the other nested_category columns to it). No need to
declare the level property specially, it's just a column like any
other, in the query you're mapping against.

    - Gulli



On Jan 30, 3:31 pm, Juan Dela Cruz <juandelacru...@gmail.com> wrote:
> Wow great ;) It really works. Thanks.
>
> One more thing, is it possible to map this in a Model Class perhaps as a
> python @property name level and make it query-able? Like passing it to a
> filter clause
>
> e.g.
> nested_category.query.filter(nested_category.c.level=='3')
>
> On Sat, Jan 30, 2010 at 8:48 AM, Gunnlaugur Briem <gunnlau...@gmail.com>wrote:
>
>
>
> > Hi Juan,
>
> > this will do it in version 10.5.8 (and probably earlier:
>
> > nested_category = Table(
> >    'nested_category',
> >    MetaData(),
> >    Column('category_id', Integer, primary_key=True),
> >    Column('name', Text, nullable=False),
> >    Column('lft', Integer, nullable=False),
> >    Column('rgt', Integer, nullable=False)
> >    )
> > node = nested_category.alias('node')
> > parent = nested_category.alias('parent')
> > query = select([node.c.name, (func.count(node.c.name) - text
> > ('1')).label('level')],
> >    from_obj=join(node, parent,
> >                  node.c.lft.between(parent.c.lft, parent.c.rgt)
> >                  )
> >    ).group_by(node.c.name)
>
> > str(query) will show that it is correct (it uses a JOIN expression
> > instead of the WHERE condition, but that's equivalent and more
> > explicit)
>
> > The text('1') instead of just 1 is so that the literal constant 1 is
> > not needlessly replaced by a bind param. It works either way though.
>
> > Regards,
>
> >    - Gulli
>
> > On Jan 29, 8:53 am, Juan Dela Cruz <juandelacru...@gmail.com> wrote:
> > > Can someone please help me to figure out the equivalent of this sql query
> > to
> > > sqlalchemy
>
> > > This my nested_category table:
>
> > > +-------------+----------------------+-----+-----+
> > > | category_id | name                 | lft | rgt |
> > > +-------------+----------------------+-----+-----+
> > > |           1 | ELECTRONICS          |   1 |  20 |
> > > |           2 | TELEVISIONS          |   2 |   9 |
> > > |           3 | TUBE                 |   3 |   4 |
> > > |           4 | LCD                  |   5 |   6 |
> > > |           5 | PLASMA               |   7 |   8 |
> > > |           6 | PORTABLE ELECTRONICS |  10 |  19 |
> > > |           7 | MP3 PLAYERS          |  11 |  14 |
> > > |           8 | FLASH                |  12 |  13 |
> > > |           9 | CD PLAYERS           |  15 |  16 |
> > > |          10 | 2 WAY RADIOS         |  17 |  18 |
> > > +-------------+----------------------+-----+-----+
>
> > > SELECT node.name, (COUNT(node.name)-1) AS level
> > >     FROM nested_category AS node, nested_category AS parent
> > >         WHERE node.lft BETWEEN parent.lft AND parent.rgt
> > >             GROUP BY node.name;
>
> > > The result will be:
> > > +----------------------+-------+
>
> > > | name                 | depth |
> > > +----------------------+-------+
> > > | ELECTRONICS          |     0 |
> > > | TELEVISIONS          |     1 |
> > > | TUBE                 |     2 |
> > > | LCD                  |     2 |
> > > | PLASMA               |     2 |
> > > | PORTABLE ELECTRONICS |     1 |
> > > | MP3 PLAYERS          |     2 |
> > > | FLASH                |     3 |
> > > | CD PLAYERS           |     2 |
> > > | 2 WAY RADIOS         |     2 |
> > > +----------------------+-------+
>
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