Did you try qry = session.query(AssetCategory).join(Asset).join(Shot).filter(Shot.id==1).distinct() qry = qry.filter(Shot.id==shot_id_of_interest)
that generates SELECT DISTINCT "AssetCategory".id AS "AssetCategory_id" FROM "AssetCategory" JOIN "Asset" ON "AssetCategory".id = "Asset".category_id JOIN "Shot" ON "Shot".id = "Asset".shot_id WHERE "Shot".id = :id_1 -- Mike Conley -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalch...@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.