Hi Timmy and Michael, I was wandering here about the same problem. I have a table that defines keys and value type (ie: key 'username', type 'unicode max 60' - that it is a constant).
Then, I have the values table, which is polymorphic on value type and also has a fk to keys table. I think it is a bit lame to duplicate value type in those two tables, and also not that useful to use the polymorphic as a "static" value on each record of value table since I already have it on keys table. By having a fk to keys table, can't I get the polymorphic value from there? Thanks in advance, Richard. On Wed, May 5, 2010 at 6:47 PM, Timmy Chan <timmy.cha...@gmail.com> wrote: > thx, that is what i am wondering. they are one-to-one, maybe thats good > enough for performance. so there's no easy way to do this. > > > On Wed, May 5, 2010 at 5:44 PM, Michael Bayer <mike...@zzzcomputing.com>wrote: > >> >> I meant SQL. if you want to do polymorphic_on based on "a.type" it >> would at the very least need to issue: >> >> SELECT c.*, a.type JOIN b ON c.b_id = b.id JOIN a ON b.a_id=a >> >> which is an expensive way to get to where you're going. It can be done >> of course but not through relation(). >> >> >> On May 5, 2010, at 5:36 PM, Timmy Chan wrote: >> >> "C"/"D" objects doesn't exist without "A" and "B"? maybe walk up the >> graph: C.b.a.type >> >> im not sure this schema is sensible, if it's really bad, please advise, im >> not attached to it! >> >> thax! >> >> On Wed, May 5, 2010 at 5:28 PM, Michael Bayer >> <mike...@zzzcomputing.com>wrote: >> >>> what query do you want to see when you select "C" and "D" objects ? >>> >>> >>> >>> On May 5, 2010, at 5:26 PM, Timmy Chan wrote: >>> >>> thx, is there a way to set that up, or something similar? >>> >>> after giving it thought, maybe polymorphic_on isn't what i need. in some >>> sense, table "A" is similar to a generic container, and i want to constrain >>> the type of "C" depending on "A"'s type column. is there a way to do this? >>> >>> On Wed, May 5, 2010 at 5:15 PM, Michael Bayer >>> <mike...@zzzcomputing.com>wrote: >>> >>>> >>>> On May 5, 2010, at 5:01 PM, Timmy Chan wrote: >>>> >>>> i have 4 tables, a, b, c, d. >>>> >>>> a has one-to-many relation with b, b with one-to-one relationship with >>>> c, c is a polymorphic on a.type, with d being one of the polymorphic types. >>>> >>>> is there a way to implement this? >>>> >>>> details: >>>> >>>> this is what im trying to do in sqlalchemy: >>>> >>>> a = Table('a', metadata, >>>> Column( 'id', Integer(), primary_key=True ), >>>> Column( 'type', UnicodeText() ) ) >>>> >>>> b = Table('b', metadata, >>>> Column( 'id', Integer(), primary_key=True ), >>>> Column( 'a_id', Integer(), ForeignKey('a.id') ) ) >>>> >>>> c = Table('c', metadata, >>>> Column( 'id', Integer(), primary_key=True ), >>>> Column( 'b_id', Integer(), ForeignKey('b.id') ), >>>> Column( 'class_id', Integer() ) ) >>>> >>>> d = Table('d', metadata, >>>> Column( 'id', Integer(), primary_key=True ), >>>> Column( 'data', Integer() ) >>>> >>>> mappers >>>> >>>> mapper( A, a ) >>>> mapper( B, b, properties={'a': relationship( A, >>>> uselist=False,backref='b', >>>> 'c':relationship( C, uselist=False, backref='b') }) >>>> >>>> # Does a full join, does not work >>>> mapper( C, c, polymorphic_on = a.c.type ) >>>> mapper( D, d, inherits=C, polymorphic_identity = "D" ) >>>> >>>> >>>> how can i change c to polymorphic on a, through the relationship? is >>>> there a way to sort by d.data? (b-c/d is one-on-one). >>>> >>>> >>>> this mapping is incorrect. mapper(C) cannot be polymorphic on a >>>> table which is not part of its mapping, and mapper(C) does not contain an >>>> "inherits" keyword to that of A. Usually the "polymorphic_on" setting is >>>> on the base-most mapper in the hierarchy and its not clear here which >>>> mapper >>>> you intend for that to be. >>>> >>>> >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "sqlalchemy" group. >>>> To post to this group, send email to sqlalch...@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> sqlalchemy+unsubscr...@googlegroups.com<sqlalchemy%2bunsubscr...@googlegroups.com> >>>> . >>>> For more options, visit this group at >>>> http://groups.google.com/group/sqlalchemy?hl=en. >>>> >>> >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "sqlalchemy" group. >>> To post to this group, send email to sqlalch...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> sqlalchemy+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/sqlalchemy?hl=en. >>> >>> >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "sqlalchemy" group. >>> To post to this group, send email to sqlalch...@googlegroups.com. >>> To unsubscribe from this group, send email to >>> sqlalchemy+unsubscr...@googlegroups.com<sqlalchemy%2bunsubscr...@googlegroups.com> >>> . >>> For more options, visit this group at >>> http://groups.google.com/group/sqlalchemy?hl=en. >>> >> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "sqlalchemy" group. >> To post to this group, send email to sqlalch...@googlegroups.com. >> To unsubscribe from this group, send email to >> sqlalchemy+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/sqlalchemy?hl=en. >> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "sqlalchemy" group. >> To post to this group, send email to sqlalch...@googlegroups.com. >> To unsubscribe from this group, send email to >> sqlalchemy+unsubscr...@googlegroups.com<sqlalchemy%2bunsubscr...@googlegroups.com> >> . >> For more options, visit this group at >> http://groups.google.com/group/sqlalchemy?hl=en. >> > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To post to this group, send email to sqlalch...@googlegroups.com. > To unsubscribe from this group, send email to > sqlalchemy+unsubscr...@googlegroups.com<sqlalchemy%2bunsubscr...@googlegroups.com> > . > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. 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