Same behavior with 0.6.3.

On Aug 3, 4:17 pm, Michael Bayer <mike...@zzzcomputing.com> wrote:
> On Aug 3, 2010, at 5:00 PM, Bryan wrote:
>
> > Python 2.5.4
> > MySQL python 1.2.3c1
> > sqlalchemy 0.5.2
>
> just curious can you try with SQLA 0.6.3 ?
>
>
>
> > Here is the actual code.  It references my object model etc so it
> > won't run for you, but just in case I made a mistake converting it to
> > a simplified version of the problem here it is:
>
> > dollars = func.if_(EmpTime.actTotal != None, EmpTime.actTotal,
> >            EmpTime.estTotal, type_=types.Numeric)
> > q = orm.query(
> >            Account.code,
> >            func.lower(TimeType.shortName),
> >            func.sum(EmpTime.hours),
> >            func.sum(dollars, type_=types.Numeric)
> >            )
> > q = q.join(EmpTime.acc).join(EmpTime.timeType)
> > q = q.group_by(Account.code).group_by(TimeType.shortName)
> > q = q.filter(EmpTime.day >= start)
> > q = q.filter(EmpTime.day <= end)
> > q = q.filter(EmpTime.jobId == jobId)
> > labor = q.all()
>
> > On Aug 3, 1:26 pm, Michael Bayer <mike...@zzzcomputing.com> wrote:
> >> On Aug 3, 2010, at 2:56 PM, Bryan wrote:
>
> >>> This returns a Decimal type for c2, which is what I want:
> >>> c1 = literal(5, type_=Numeric)
> >>> c2 = func.sum(c1, type_=Numeric)
>
> >>> This returns a Float type for c2, but I'm telling c1 that it is a
> >>> Numeric.  How can I get a decimal returned when using an if function?
> >>> c1 = func.if_(Table.foo != None, Table.foo, Table.bar, type_=Numeric)
> >>> c2 = func.sum(c1, type_=Numeric)
>
> >> I see nothing wrong with that code.    Can I get some SQLA version / 
> >> database backend / DBAPI details ?
>
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