Table is not meant for subclassing, so you would need to read the source code
to understand these issues. The issue below cannot be reproduced:
from sqlalchemy import *
class MyTable(Table):
def __init__(self, name, metadata, *args, **kwargs):
super(MyTable, self).__init__(name, metadata, *args, **kwargs)
def bar(self):
return "hi"
m = MetaData()
mt = MyTable('foo', m, Column('id', Integer))
print mt.bar()
0.7 output:
hi
0.6 output:
hi
0.5 output:
hi
On Feb 22, 2011, at 8:30 AM, bool wrote:
> I wrote a simple subclass of Table
>
> ====================================================
> class MyTable(Table):
>
> def __init__(self, name, metadata, *args, **kwargs):
> """
> """
> super(MyTable, self).__init__(name, metadata, *args, **kwargs)
>
>
> def select(self, whereclause=None):
> return super(BitemporalTable, self).select(self.c.z > 1)
> ==================================================
>
> select(t) where t is an object of MyTable is giving this error. What
> is the solution...
>
> Traceback (most recent call last):
> File "t.py", line 16, in <module>
> select(t)
> File "/prod/tools/infra/SQLAlchemy-0.5.5-py2.5.egg/sqlalchemy/sql/
> expression.py", line 246, in select
> s = Select(columns, whereclause=whereclause, from_obj=from_obj,
> **kwargs)
> File "/prod/tools/infra/SQLAlchemy-0.5.5-py2.5.egg/sqlalchemy/sql/
> expression.py", line 3239, in __init__
> [_literal_as_column(c) for c in columns]
> TypeError: 'MyTable' object is not iterable
>
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