the UNION stuff in query() took awhile to get right and had a lot of bugs in the 0.5 days. If you try 0.7, you'll get:
SELECT anon_1.type AS anon_1_type FROM (SELECT 'Phrase' AS type UNION SELECT 'Exact' AS type) AS anon_1 so old bug, either work with SQL expressions (i.e. tables, select(), etc.) and pass to session.execute(), or work on upgrading to a more recent SQLAlchemy. On Dec 9, 2011, at 5:29 PM, Alex Parij wrote: > Hi , > > I'm using SA 0.5. > query1 = session.query(literal_column("'Phrase'").label('type')).filter(...) > query2 = session.query(literal_column("'Exact'").label('type')).filter(...) > > and then : > query1.union(query2) > gives me : > > SELECT 'Phrase' as type > FROM (SELECT 'Phrase' as type FROM table1 WHERE .... > UNION > SELECT 'Exact' as type FROM table1 WHERE .... > ) AS anon_1 > > But I need : > > SELECT type > FROM ( > SELECT 'Phrase' AS type FROM table1 WHERE ... > UNION > SELECT 'Exact' AS type FROM table1 WHERE... > ) AS anon_1 > > Any ideas how I can fix the outer select? > > Thanks ! > > -- > You received this message because you are subscribed to the Google Groups > "sqlalchemy" group. > To view this discussion on the web visit > https://groups.google.com/d/msg/sqlalchemy/-/K4EEBKA4WvAJ. > To post to this group, send email to sqlalchemy@googlegroups.com. > To unsubscribe from this group, send email to > sqlalchemy+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/sqlalchemy?hl=en. -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com. To unsubscribe from this group, send email to sqlalchemy+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.