Thank you for your reply Wichert, I already used the Inspector method
get_table_names(), but using that I'd have to check if a table name is
present in a vector which can have 100.000 elements. This can be even
slower if done for lots of times. Maybe I can perform a binary search,
but I'm not sure that the resulting vector is ordered. Am I wrong?
Other Ideas?

On 25 Apr, 16:11, Wichert Akkerman <wich...@wiggy.net> wrote:
> On 04/25/2012 03:57 PM, Massi wrote:
>
>
>
>
>
>
>
>
>
> > Hi everyone,
>
> > in my script I have to deal with a huge database with thousands of
> > tables. Given a table name (a python string) I would have to now if
> > such a table exists or not. Up to now I have written this function:
>
> > def DBGetTableByName(table_name) :
> >          metadata = MetaData(engine)
> >          try :
> >              table = Table(table_name, metadata, autoload=True)
> >              return table
> >          except NoSuchTableError :
> >              return None
>
> > I use its return value to check if the table exists, but the problem
> > is that it is too slow. Since I have to repeat this operation several
> > times I wonder if there is a faster (and smarter) way to perform this
> > control.
> > Any hints?
>
> Use the inspector:
>
> from sqlalchemy.engine.reflection import Inspector
>
> inspector = Inspector.from_engine(engine)
> print table_name in inspector.get_table_names()
>
> You can find the documentation 
> here:http://docs.sqlalchemy.org/en/rel_0_7/core/schema.html?highlight=insp...
>
> Wichert.

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