Thanks Michael.

The question is: how can I use that trick as a relation?

I can do:

session.query(Node).outerjoin(Node.right_nodes)

and

session.query(Node).outerjoin(Node.left_nodes) 

but not

session.query(Node).outerjoin(Node.all_nodes) 

and that is what I'm looking for. I mean the relation() functionality.

Is there some way to accomplish that?


Thanks again!

Adolfo

On Monday, August 20, 2012 5:35:51 PM UTC-5, Michael Bayer wrote:
>
>
> On Aug 20, 2012, at 6:07 PM, adolfo wrote:
>
> I have a Self-Referential Many-to-Many Relationship situation where the 
>
> right_nodes = relationship("Node",
>                         secondary=node_to_node,
>                         primaryjoin=id==node_to_node.c.left_node_id,
>                         secondaryjoin=id==node_to_node.c.right_node_id,
>                         backref="left_nodes"
>
>
> works fine.
> The problem:
> I need a "related nodes" relationship, which, in one expression, returns 
> all related nodes, both left nodes and right nodes, excluding the given 
> node itself.
> Is that possible using the RELATIONSHIP construct?
>
>
> this is the "my friends and people who I'm friends with" query and the 
> recipe is....well I guess I didn't put it up anywhere yet, the idea is to 
> use a @property:
>
> class MyClass(Base):
>     # ...
>
>    @property
>    def all_nodes(self):
>        return self.left_nodes + self.right_nodes
>
> to do this in SQL only requires a UNION in a subquery.  If you really 
> wanted that I can work it out, it's more burdensome but if you have a 
> specific query style in mind it could be useful.
>
>

-- 
You received this message because you are subscribed to the Google Groups 
"sqlalchemy" group.
To view this discussion on the web visit 
https://groups.google.com/d/msg/sqlalchemy/-/W5_3pjXf2V4J.
To post to this group, send email to sqlalchemy@googlegroups.com.
To unsubscribe from this group, send email to 
sqlalchemy+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/sqlalchemy?hl=en.

Reply via email to